Ответ:
\[a_{1} = - 1;\ \ a_{2} = 2;\ \ a_{3} = 5:\]
\[d = a_{2} - a_{1} = 2 + 1 = 3;\]
\[S_{5} = \frac{2a_{1} + d(n - 1)}{2} \cdot n =\]
\[= \frac{- 2 + 3(5 - 1)}{2} \cdot 5 =\]
\[= \frac{- 2 + 12}{2} \cdot 5 = 5 \cdot 5 = 25.\]
\[a_{1} = - 1;\ \ a_{2} = 2;\ \ a_{3} = 5:\]
\[d = a_{2} - a_{1} = 2 + 1 = 3;\]
\[S_{5} = \frac{2a_{1} + d(n - 1)}{2} \cdot n =\]
\[= \frac{- 2 + 3(5 - 1)}{2} \cdot 5 =\]
\[= \frac{- 2 + 12}{2} \cdot 5 = 5 \cdot 5 = 25.\]