3. Вычислите: $$13 - (3 - 1 \frac{20}{21}) : \frac{4}{49} + \frac{3}{10}$$.
Решение:
- \(3 - 1 \frac{20}{21} = \frac{3}{1}^{\frac{21}{}} - \frac{41}{21} = \frac{63 - 41}{21} = \frac{22}{21}\)
- \(\frac{22}{21} : \frac{4}{49} = \frac{22}{21} \cdot \frac{49}{4} = \frac{22 \cdot 49}{21 \cdot 4} = \frac{11 \cdot 7}{3 \cdot 2} = \frac{77}{6}\)
- \(13 - \frac{77}{6} + \frac{3}{10} = \frac{13}{1}^{\frac{30}{}} - \frac{77}{6}^{\frac{5}{}} + \frac{3}{10}^{\frac{3}{}} = \frac{390}{30} - \frac{385}{30} + \frac{9}{30} = \frac{390 - 385 + 9}{30} = \frac{5 + 9}{30} = \frac{14}{30} = \frac{7}{15}\)
Ответ: $$\frac{7}{15}$$