1. Вычислите: $$-\frac{8}{5} + \frac{21}{25} \cdot 1 \frac{17}{28} + 2 : 3 \frac{9}{17}$$.
Решение:
- \(\frac{21}{25} \cdot 1 \frac{17}{28} = \frac{21}{25} \cdot \frac{45}{28} = \frac{21 \cdot 45}{25 \cdot 28} = \frac{3 \cdot 9}{5 \cdot 4} = \frac{27}{20}\)
- \(2 : 3 \frac{9}{17} = 2 : \frac{60}{17} = 2 \cdot \frac{17}{60} = \frac{2 \cdot 17}{60} = \frac{17}{30}\)
- \(-\frac{8}{5} + \frac{27}{20} + \frac{17}{30} = -\frac{8}{5}^{\frac{12}{}} + \frac{27}{20}^{\frac{3}{}} + \frac{17}{30}^{\frac{2}{}} = -\frac{96}{60} + \frac{81}{60} + \frac{34}{60} = \frac{-96 + 81 + 34}{60} = \frac{-15 + 34}{60} = \frac{19}{60}\)
Ответ: $$\frac{19}{60}$$