Вопрос:

Вычислите: 1) $$5 \frac{1}{7} : 3 \frac{1}{3}$$; 2) $$\frac{4}{9} : 4 \frac{5}{6}$$; 3) $$7 \frac{1}{3} : \frac{2}{5}$$; 4) $$6 \frac{1}{8} : 7$$; 5) $$6 : 2 \frac{4}{7}$$; 6) $$1 \frac{5}{6} : 4 \frac{5}{6}$$; 7) $$7 \frac{1}{9} : 1$$; 8) $$0 : 3 \frac{2}{7}$$; 9) $$5 \frac{8}{9} : 0$$.

Ответ:

  1. $$5 \frac{1}{7} : 3 \frac{1}{3} = \frac{36}{7} : \frac{10}{3} = \frac{36}{7} \cdot \frac{3}{10} = \frac{36 \cdot 3}{7 \cdot 10} = \frac{18 \cdot 3}{7 \cdot 5} = \frac{54}{35} = 1 \frac{19}{35}$$
  2. $$\frac{4}{9} : 4 \frac{5}{6} = \frac{4}{9} : \frac{29}{6} = \frac{4}{9} \cdot \frac{6}{29} = \frac{4 \cdot 6}{9 \cdot 29} = \frac{4 \cdot 2}{3 \cdot 29} = \frac{8}{87}$$
  3. $$7 \frac{1}{3} : \frac{2}{5} = \frac{22}{3} : \frac{2}{5} = \frac{22}{3} \cdot \frac{5}{2} = \frac{11 \cdot 5}{3 \cdot 1} = \frac{55}{3} = 18 \frac{1}{3}$$
  4. $$6 \frac{1}{8} : 7 = \frac{49}{8} : 7 = \frac{49}{8} \cdot \frac{1}{7} = \frac{7 \cdot 1}{8 \cdot 1} = \frac{7}{8}$$
  5. $$6 : 2 \frac{4}{7} = 6 : \frac{18}{7} = 6 \cdot \frac{7}{18} = \frac{6 \cdot 7}{18} = \frac{1 \cdot 7}{3} = \frac{7}{3} = 2 \frac{1}{3}$$
  6. $$1 \frac{5}{6} : 4 \frac{5}{6} = \frac{11}{6} : \frac{29}{6} = \frac{11}{6} \cdot \frac{6}{29} = \frac{11 \cdot 1}{1 \cdot 29} = \frac{11}{29}$$
  7. $$7 \frac{1}{9} : 1 = \frac{64}{9} : 1 = \frac{64}{9} \cdot 1 = \frac{64}{9} = 7 \frac{1}{9}$$
  8. $$0 : 3 \frac{2}{7} = 0 : \frac{23}{7} = 0 \cdot \frac{7}{23} = 0$$
  9. $$5 \frac{8}{9} : 0 = \frac{53}{9} : 0$$ - деление на ноль не определено.
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