Ответ:
Преобразуем смешанные числа:
\(2\frac{1}{4}=\frac{9}{4}\), \(27\frac{7}{10}=\frac{277}{10}\), \(14\frac{2}{3}=\frac{44}{3}\), \(3\frac{4}{5}=\frac{19}{5}\), \(9\frac{1}{2}=\frac{19}{2}\).
\(\frac{9}{4}\cdot7+\left(\frac{277}{10}:3-\frac{44}{3}:2\right):\frac{19}{5}-\frac{19}{2}\)
\(=\frac{63}{4}+\left(\frac{277}{30}-\frac{22}{3}\right)\cdot\frac{5}{19}-\frac{19}{2}\)
\(=\frac{63}{4}+\frac{19}{10}\cdot\frac{5}{19}-\frac{19}{2}=\frac{63}{4}+\frac12-\frac{19}{2}=\frac{45}{4}=11.25\).
Ответ: 11,25.
