<p>a) \begin{aligned}
\frac{2}{3} x^2 y^8 \cdot (-\frac{1}{2} x y^3)^4 &= \frac{2}{3} x^2 y^8 \cdot \frac{1}{16} x^4 y^{12} = \frac{2}{3 \cdot 16} x^{2+4} y^{8+12} = \frac{1}{24} x^6 y^{20}
\end{aligned}</p>
<p><strong>Ответ: $$\frac{1}{24} x^6 y^{20}$$</strong></p>
<p>б) \begin{aligned}
x^{n-2} \cdot x^3 \cdot x^{-n} \cdot x &= x^{n-2+3-n+1} = x^{n-n+2} = x^2
\end{aligned}</p>
<p><strong>Ответ: $$x^2$$</strong></p>