a) 6x⁻⁵y⁷⋅2,5xy⁻⁶
Разбираемся: 6 ⋅ 2,5 ⋅ x⁽⁻⁵⁺¹⁾ ⋅ y⁽⁷⁻⁶⁾ = 15x⁻⁴y¹ = \(\frac{15y}{x⁴} \).
a) 3,2a²b⁶:(0,8a³b⁻³)
Смотри, как это работает: \(\frac{3,2}{0,8} \) ⋅ a⁽²⁻³⁾ ⋅ b⁽⁶⁻⁽⁻³⁾⁾ = 4a⁻¹b⁹ = \(\frac{4b⁹}{a} \).
a) \(\frac{13x⁻⁴}{y⁻⁶} \) : \(\frac{y}{52x⁻⁵} \)
Логика такая: \(\frac{13x⁻⁴}{y⁻⁶} \) ⋅ \(\frac{52x⁻⁵}{y} \) = \(\frac{13 ⋅ 52 ⋅ x⁽⁻⁴⁻⁵⁾}{y⁽⁻⁶⁺¹⁾} = \frac{676x⁻⁹}{y⁻⁵} = \frac{676y⁵}{x⁹} \).
a) (\(\frac{9m⁻³}{5n⁻¹} \))⁻²⋅81m⁻⁶n³
Смотри, как это работает: (\(\frac{9m⁻³}{5n⁻¹} \))⁻² ⋅ 81m⁻⁶n³ = \(\frac{9⁻²m⁶}{5⁻²n⁻²} \) ⋅ 81m⁻⁶n³ = \(\frac{5²n² ⋅ 81n³}{9²m⁶ ⋅ m⁶} = \frac{25 ⋅ 81 ⋅ n⁵}{81 ⋅ m¹²} = \frac{25n⁵}{m¹²} \).
б) 0,8a⁻⁶b⁴⋅5a¹²b⁻⁴
0, 8 ⋅ 5 ⋅ a⁽⁻⁶⁺¹²⁾ ⋅ b⁽⁴⁻⁴⁾ = 4a⁶b⁰ = 4a⁶.
б) \(\frac{3}{2} \)m⁻¹n⁻⁷:(-\(\frac{7}{8} \)m⁻⁵n⁻⁷)
Разбираемся: \(\frac{3}{2} \) : (-\(\frac{7}{8} \)) ⋅ m⁽⁻¹⁻⁽⁻⁵⁾⁾ ⋅ n⁽⁻⁷⁻⁽⁻⁷⁾⁾ = -\(\frac{3}{2} \) ⋅ \(\frac{8}{7} \) ⋅ m⁴ ⋅ n⁰ = -\(\frac{12}{7} \)m⁴.
б) \(\frac{21a⁻⁴}{10b⁻³} \) : \(\frac{5b⁻⁶}{7a⁻⁸} \)
Логика такая: \(\frac{21a⁻⁴}{10b⁻³} \) ⋅ \(\frac{7a⁻⁸}{5b⁻⁶} \) = \(\frac{21 ⋅ 7 ⋅ a⁽⁻⁴⁺⁸⁾}{10 ⋅ 5 ⋅ b⁽⁻³⁺⁶⁾} = \frac{147a⁴}{50b³} \).
б) (\(\frac{2x⁴}{y⁹} \))⁻³⋅(x⁻²y)⁻⁶
Разбираемся: (\(\frac{2x⁴}{y⁹} \))⁻³ ⋅ (x⁻²y)⁻⁶ = \(\frac{2⁻³x⁻¹²}{y⁻²⁷} \) ⋅ x¹²y⁻⁶ = \(\frac{x⁰}{2³y⁽⁶⁺²⁷⁾} = \frac{1}{8y³³} \).