$$\frac{4}{7}x + \frac{5}{14}x \text{ при } x = 5\frac{1}{4}$$
$$\frac{4}{7}x + \frac{5}{14}x = x\left(\frac{4}{7} + \frac{5}{14}\right) = x\left(\frac{4 \cdot 2}{7 \cdot 2} + \frac{5}{14}\right) = x\left(\frac{8}{14} + \frac{5}{14}\right) = x\left(\frac{13}{14}\right) = \frac{13}{14}x$$
$$\text{Если } x = 5\frac{1}{4}, \text{ то } \frac{13}{14} \cdot 5\frac{1}{4} = \frac{13}{14} \cdot \frac{5 \cdot 4 + 1}{4} = \frac{13}{14} \cdot \frac{21}{4} = \frac{13 \cdot 21}{14 \cdot 4} = \frac{13 \cdot 3}{2 \cdot 4} = \frac{39}{8} = 4\frac{7}{8}$$
Ответ: $$4\frac{7}{8}$$