tg(x-$$rac{\pi}{3}$$)=√3

Решим уравнение tg(x-$$rac{\pi}{3}$$)=√3. $$tg(x-\frac{\pi}{3}) = \sqrt{3}$$ $$x-\frac{\pi}{3} = arctg(\sqrt{3}) + \pi n, n \in Z$$ $$x-\frac{\pi}{3} = \frac{\pi}{3} + \pi n, n \in Z$$ $$x = \frac{2\pi}{3} + \pi n, n \in Z$$ Ответ: $$x = \frac{2\pi}{3} + \pi n, n \in Z$$