3. Решите уравнение: a) 22-x2=0 б) 9у2-25 = 0 в) (2-x)²-x(x+1,5)=4

а) \[2^2 - x^2 = 0 \Rightarrow 4 - x^2 = 0 \Rightarrow (2-x)(2+x) = 0\]

\[2-x = 0 \Rightarrow x = 2\]

\[2+x = 0 \Rightarrow x = -2\]

б) \[9y^2 - 25 = 0 \Rightarrow (3y)^2 - 5^2 = 0 \Rightarrow (3y-5)(3y+5) = 0\]

\[3y - 5 = 0 \Rightarrow 3y = 5 \Rightarrow y = \frac{5}{3}\]

\[3y + 5 = 0 \Rightarrow 3y = -5 \Rightarrow y = -\frac{5}{3}\]

в) \[(2-x)^2 - x(x+1.5) = 4 \Rightarrow 4 - 4x + x^2 - x^2 - 1.5x = 4 \Rightarrow -5.5x = 0 \Rightarrow x = 0\]