Ответ:
\[x^{2} + 12x + 27 = 0\]
\[x_{1} + x_{2} = - 12;\ \ \ x_{1} \cdot x_{2} = 27\]
\[x_{1} = - 9;\ \ \ \ x_{2} = - 3.\]
\[Ответ:x = - 9;\ \ \ x = - 3.\]
\[x^{2} + 12x + 27 = 0\]
\[x_{1} + x_{2} = - 12;\ \ \ x_{1} \cdot x_{2} = 27\]
\[x_{1} = - 9;\ \ \ \ x_{2} = - 3.\]
\[Ответ:x = - 9;\ \ \ x = - 3.\]