Решим уравнение:
$$ (x - 2) (x - 4) = 8 $$
$$ x^2 - 4x - 2x + 8 = 8$$
$$ x^2 - 6x + 8 - 8 = 0$$
$$ x^2 - 6x = 0$$
$$ x (x - 6) = 0$$
$$ x_1 = 0 $$
$$ x - 6 = 0 $$
$$ x_2 = 6$$
Ответ: 0; 6