Окей, давай решим уравнение.
Сначала упростим уравнение:
\(\frac{8y - 2}{1 \frac{1}{3}} = \frac{3y + 1}{0,8}\)
\(1 \frac{1}{3} = \frac{4}{3}\)
\(\frac{8y - 2}{\frac{4}{3}} = \frac{3y + 1}{0,8}\)
\((8y - 2) \cdot \frac{3}{4} = \frac{3y + 1}{0,8}\)
\(\frac{3(8y - 2)}{4} = \frac{3y + 1}{0,8}\)
\(0,8 \cdot 3(8y - 2) = 4(3y + 1)\)
\(2,4(8y - 2) = 12y + 4\)
\(19,2y - 4,8 = 12y + 4\)
\(19,2y - 12y = 4 + 4,8\)
\(7,2y = 8,8\)
\(y = \frac{8,8}{7,2} = \frac{88}{72} = \frac{11}{9}\)
\(y = 1 \frac{2}{9}\)
Ответ: y = 1 \(\frac{2}{9}\)