Практика:
Получите дробь, равную данной, используя дополнительный множитель:
- \(\frac{1}{4} = \frac{1 \cdot 7}{4 \cdot 7} = \frac{7}{28}\)
- \(4\frac{7}{12} = \frac{4 \cdot 12 + 7}{12} = \frac{48+7}{12} = \frac{55}{12}\)
- \(\frac{5}{6} = \frac{5 \cdot 6}{6 \cdot 6} = \frac{30}{36}\)
- \(3\frac{5}{11} = \frac{3 \cdot 11 + 5}{11} = \frac{33+5}{11} = \frac{38}{11}\)
- \(1\frac{3}{5} = \frac{1 \cdot 5 + 3}{5} = \frac{5+3}{5} = \frac{8}{5}\)
- \(40\frac{1}{5} = \frac{40 \cdot 5 + 1}{5} = \frac{200+1}{5} = \frac{201}{5}\)
- \(10\frac{6}{7} = \frac{10 \cdot 7 + 6}{7} = \frac{70+6}{7} = \frac{76}{7}\)
- \(6\frac{12}{17} = \frac{6 \cdot 17 + 12}{17} = \frac{102+12}{17} = \frac{114}{17}\)
- \(\frac{7}{8} = \frac{7 \cdot 10}{8 \cdot 10} = \frac{70}{80}\)
- \(5\frac{2}{11} = \frac{5 \cdot 11 + 2}{11} = \frac{55+2}{11} = \frac{57}{11}\)
- \(\frac{9}{10} = \frac{9 \cdot 11}{10 \cdot 11} = \frac{99}{110}\)
- \(7\frac{2}{18} = \frac{7 \cdot 18 + 2}{18} = \frac{126+2}{18} = \frac{128}{18}\)