Решение:

а)

`$$ \frac{37,12 - 5,6 : 0,14}{1,21 + 3,4 - 0,35} = \frac{37,12 - 40}{1,21 + 3,4 - 0,35} = \frac{-2,88}{4,21 - 0,35} = \frac{-2,88}{3,86} = -\frac{288}{386} = -\frac{144}{193} \approx -0,746 $$ `

б)

`$$(2,17 \cdot 3,7 - 1,83 \cdot 2,3) : 19,1 = (8,029 - 4,209) : 19,1 = 3,82 : 19,1 = 0,2$$ `

в)

`$$5\frac{4}{19} \cdot 3\frac{4}{7} + 1\frac{15}{19} : \frac{7}{25} - 1\frac{2}{3} = \frac{99}{19} \cdot \frac{25}{7} + \frac{34}{19} : \frac{7}{25} - \frac{5}{3} = \frac{2475}{133} + \frac{34}{19} \cdot \frac{25}{7} - \frac{5}{3} = \frac{2475}{133} + \frac{850}{133} - \frac{5}{3} = \frac{3325}{133} - \frac{5}{3} = \frac{9975 - 665}{399} = \frac{9310}{399} \approx 23,33$$ `

г)

`$$5\frac{3}{7} - (2\frac{1}{2} + 1\frac{1}{3}) : \frac{1}{6} = \frac{38}{7} - (\frac{5}{2} + \frac{4}{3}) : \frac{1}{6} = \frac{38}{7} - (\frac{15+8}{6}) : \frac{1}{6} = \frac{38}{7} - \frac{23}{6} \cdot 6 = \frac{38}{7} - 23 = \frac{38 - 161}{7} = -\frac{123}{7} \approx -17,57$$ `

д)

`$$(2\frac{7}{15} + 1\frac{7}{12}) \cdot 1\frac{1}{9} - 1\frac{7}{8} = (\frac{37}{15} + \frac{19}{12}) \cdot \frac{10}{9} - \frac{15}{8} = (\frac{148 + 95}{60}) \cdot \frac{10}{9} - \frac{15}{8} = \frac{243}{60} \cdot \frac{10}{9} - \frac{15}{8} = \frac{2430}{540} - \frac{15}{8} = \frac{27}{6} - \frac{15}{8} = \frac{9}{2} - \frac{15}{8} = \frac{36 - 15}{8} = \frac{21}{8} = 2\frac{5}{8} = 2,625$$ `

e)

`$$(6\frac{1}{7} - 5\frac{3}{4}) : \frac{11}{14} + (3\frac{3}{4} - 1\frac{5}{6}) : \frac{1}{6} = (\frac{43}{7} - \frac{23}{4}) : \frac{11}{14} + (\frac{15}{4} - \frac{11}{6}) : \frac{1}{6} = (\frac{172 - 161}{28}) : \frac{11}{14} + (\frac{45 - 22}{12}) : \frac{1}{6} = \frac{11}{28} \cdot \frac{14}{11} + \frac{23}{12} \cdot 6 = \frac{1}{2} + \frac{23}{2} = \frac{24}{2} = 12$$ `