Вопрос:

2 Найдите значение выражения: a) \(\frac{3}{14} + (\frac{2}{7} + \frac{1}{2})\); б) \(\frac{11}{56} + (\frac{6}{7} - \frac{3}{8})\); в) (\(\frac{5}{8} + \frac{1}{6}\)) - \(\frac{7}{24}\); г) \(\frac{15}{36} - (\frac{1}{3} - \frac{1}{12}\)).

Смотреть решения всех заданий с листа

Ответ:

Найдем значение выражения: a) \(\frac{3}{14} + (\frac{2}{7} + \frac{1}{2})\) = \(\frac{3}{14} + (\frac{2 \cdot 2}{7 \cdot 2} + \frac{1 \cdot 7}{2 \cdot 7})\) = \(\frac{3}{14} + (\frac{4}{14} + \frac{7}{14})\) = \(\frac{3}{14} + \frac{11}{14}\) = \(\frac{3 + 11}{14}\) = \(\frac{14}{14}\) = 1. б) \(\frac{11}{56} + (\frac{6}{7} - \frac{3}{8})\) = \(\frac{11}{56} + (\frac{6 \cdot 8}{7 \cdot 8} - \frac{3 \cdot 7}{8 \cdot 7})\) = \(\frac{11}{56} + (\frac{48}{56} - \frac{21}{56})\) = \(\frac{11}{56} + \frac{27}{56}\) = \(\frac{11 + 27}{56}\) = \(\frac{38}{56}\) = \(\frac{19}{28}\). в) (\(\frac{5}{8} + \frac{1}{6}\)) - \(\frac{7}{24}\) = (\(\frac{5 \cdot 3}{8 \cdot 3} + \frac{1 \cdot 4}{6 \cdot 4}\)) - \(\frac{7}{24}\) = (\(\frac{15}{24} + \frac{4}{24}\)) - \(\frac{7}{24}\) = \(\frac{19}{24} - \frac{7}{24}\) = \(\frac{19 - 7}{24}\) = \(\frac{12}{24}\) = \(\frac{1}{2}\). г) \(\frac{15}{36} - (\frac{1}{3} - \frac{1}{12}\)) = \(\frac{15}{36} - (\frac{1 \cdot 4}{3 \cdot 4} - \frac{1}{12}\)) = \(\frac{15}{36} - (\frac{4}{12} - \frac{1}{12}\)) = \(\frac{15}{36} - \frac{3}{12}\) = \(\frac{15}{36} - \frac{3 \cdot 3}{12 \cdot 3}\) = \(\frac{15}{36} - \frac{9}{36}\) = \(\frac{15 - 9}{36}\) = \(\frac{6}{36}\) = \(\frac{1}{6}\). Ответ: а) 1; б) \(\frac{19}{28}\); в) \(\frac{1}{2}\); г) \(\frac{1}{6}\).
ГДЗ по фото 📸

Похожие