4. Найдите значение выражения:
\(0,6+1\frac{1}{26}\cdot(6-2\frac{3}{11}:\frac{9}{11}) = \frac{6}{10}+\frac{27}{26}\cdot(6-\frac{25}{11}:\frac{9}{11}) = \frac{3}{5}+\frac{27}{26}\cdot(6-\frac{25}{11}\cdot\frac{11}{9})=\frac{3}{5}+\frac{27}{26}\cdot(6-\frac{25}{9}) = \frac{3}{5}+\frac{27}{26}\cdot(\frac{54}{9}-\frac{25}{9}) = \frac{3}{5}+\frac{27}{26}\cdot\frac{29}{9} = \frac{3}{5}+\frac{3}{26}\cdot29 = \frac{3}{5}+\frac{87}{26} = \frac{3\cdot26}{5\cdot26}+\frac{87\cdot5}{26\cdot5} = \frac{78}{130}+\frac{435}{130} = \frac{513}{130} = 3\frac{123}{130}\)
Ответ: \(3\frac{123}{130}\)