Найдите разность: a) $$1\frac{4}{17} - \frac{7}{17}$$; б) $$6 - 5\frac{6}{11}$$; в) $$17\frac{2}{3} - 6\frac{7}{8}$$; г) $$4\frac{9}{16} - 2\frac{3}{14}$$; д) $$11\frac{7}{32} - 9\frac{11}{64}$$; e) $$24\frac{7}{15} - 15\frac{5}{12}$$

Решим примеры по порядку: a) $$1\frac{4}{17} - \frac{7}{17} = \frac{1\cdot17 + 4}{17} - \frac{7}{17} = \frac{21}{17} - \frac{7}{17} = \frac{21-7}{17} = \frac{14}{17}$$ б) $$6 - 5\frac{6}{11} = 6 - \frac{5\cdot11 + 6}{11} = 6 - \frac{61}{11} = \frac{6\cdot11}{11} - \frac{61}{11} = \frac{66}{11} - \frac{61}{11} = \frac{66-61}{11} = \frac{5}{11}$$ в) $$17\frac{2}{3} - 6\frac{7}{8} = \frac{17\cdot3 + 2}{3} - \frac{6\cdot8 + 7}{8} = \frac{53}{3} - \frac{55}{8} = \frac{53\cdot8}{3\cdot8} - \frac{55\cdot3}{8\cdot3} = \frac{424}{24} - \frac{165}{24} = \frac{424-165}{24} = \frac{259}{24} = 10\frac{19}{24}$$ г) $$4\frac{9}{16} - 2\frac{3}{14} = \frac{4\cdot16 + 9}{16} - \frac{2\cdot14 + 3}{14} = \frac{73}{16} - \frac{31}{14} = \frac{73\cdot14}{16\cdot14} - \frac{31\cdot16}{14\cdot16} = \frac{1022}{224} - \frac{496}{224} = \frac{1022-496}{224} = \frac{526}{224} = \frac{263}{112} = 2\frac{39}{112}$$ д) $$11\frac{7}{32} - 9\frac{11}{64} = \frac{11\cdot32 + 7}{32} - \frac{9\cdot64 + 11}{64} = \frac{359}{32} - \frac{587}{64} = \frac{359\cdot2}{32\cdot2} - \frac{587}{64} = \frac{718}{64} - \frac{587}{64} = \frac{718-587}{64} = \frac{131}{64} = 2\frac{3}{64}$$ e) $$24\frac{7}{15} - 15\frac{5}{12} = \frac{24\cdot15 + 7}{15} - \frac{15\cdot12 + 5}{12} = \frac{367}{15} - \frac{185}{12} = \frac{367\cdot4}{15\cdot4} - \frac{185\cdot5}{12\cdot5} = \frac{1468}{60} - \frac{925}{60} = \frac{1468-925}{60} = \frac{543}{60} = \frac{181}{20} = 9\frac{1}{20}$$ <strong>Ответ:</strong> a) $$\frac{14}{17}$$ б) $$\frac{5}{11}$$ в) $$10\frac{19}{24}$$ г) $$2\frac{39}{112}$$ д) $$2\frac{3}{64}$$ e) $$9\frac{1}{20}$$