150. Найдите корень уравнения: a) (y + 4) - (y - 1) = 6y; б) 3p-1-(p + 3) = 1; в) 6x - (7х - 12) = 101; г) 20x = 19 - (3 + 12x).

a) (y + 4) - (y - 1) = 6y $$y + 4 - y + 1 = 6y$$ $$5 = 6y$$ $$y = \frac{5}{6}$$   б) 3p - 1 - (p + 3) = 1 $$3p - 1 - p - 3 = 1$$ $$2p - 4 = 1$$ $$2p = 5$$ $$p = \frac{5}{2}$$ $$p = 2,5$$   в) 6x - (7x - 12) = 101 $$6x - 7x + 12 = 101$$ $$-x = 101 - 12$$ $$-x = 89$$ $$x = -89$$   г) 20x = 19 - (3 + 12x) $$20x = 19 - 3 - 12x$$ $$20x + 12x = 16$$ $$32x = 16$$ $$x = \frac{16}{32}$$ $$x = \frac{1}{2}$$ $$x = 0,5$$ <p><strong>Ответ: а) y = $$\frac{5}{6}$$; б) p = 2,5; в) x = -89; г) x = 0,5.</strong></p>