3) 1/22 ху³, если х = -11, y = 4;

3) $$\frac{1}{22}xy^3 = \frac{1}{22} \cdot (-11) \cdot 4^3 = \frac{1}{22} \cdot (-11) \cdot 64 = - \frac{11 \cdot 64}{22} = - \frac{64}{2} = -32$$

Ответ: -32