г) $$\frac{3}{4}n + \frac{2}{3}n - \frac{4}{18}n$$ при $$n = 1\frac{13}{23}; \frac{6}{41}$$.

г) $$\frac{3}{4}n + \frac{2}{3}n - \frac{4}{18}n$$ при $$n = 1\frac{13}{23} = \frac{36}{23}; n = \frac{6}{41}$$.

$$\frac{3}{4}n + \frac{2}{3}n - \frac{4}{18}n = \frac{3^{(9}}{4}n + \frac{2^{(12}}{3}n - \frac{4^{(2}}{18}n = \frac{27}{36}n + \frac{24}{36}n - \frac{8}{36}n = \frac{27+24-8}{36}n = \frac{43}{36}n$$

При $$n = \frac{36}{23}$$:

$$\frac{43}{36} \cdot \frac{36}{23} = \frac{43}{23} = 1\frac{20}{23}$$

При $$n = \frac{6}{41}$$:

$$\frac{43}{36} \cdot \frac{6}{41} = \frac{43}{6 \cdot 6} \cdot \frac{6}{41} = \frac{43}{6 \cdot 41} = \frac{43}{246}$$

Ответ: $$1\frac{20}{23}$$ и $$\frac{43}{246}$$