e) \frac{16p^{2}q^{3}-24p^{3}q^{4}}{12p^{2}q^{3}-8pq^{2}} = \frac{8p^{2}q^{3}(2-3pq)}{4pq^{2}(3pq-2)} = - \frac{8p^{2}q^{3}(3pq-2)}{4pq^{2}(3pq-2)} = -2pq
Ответ: -2pq