б) \(\frac{3x+2y}{2x-3y} - \frac{x-8y}{3y-2x}\);

б) \(\frac{3x+2y}{2x-3y} - \frac{x-8y}{3y-2x}\);

Преобразуем выражение:

\(\frac{3x+2y}{2x-3y} - \frac{x-8y}{3y-2x} = \frac{3x+2y}{2x-3y} + \frac{x-8y}{2x-3y} = \frac{3x+2y+x-8y}{2x-3y} = \frac{4x-6y}{2x-3y} = \frac{2(2x-3y)}{2x-3y} = 2\)

Ответ: 2