б) \((\frac{1}{3})^2+(\frac{1}{3})^3\).

1) \((\frac{1}{3})^2 = \frac{1}{3} \cdot \frac{1}{3} = \frac{1}{9}\)

2) \((\frac{1}{3})^3 = \frac{1}{3} \cdot \frac{1}{3} \cdot \frac{1}{3} = \frac{1}{27}\)

3) \(\frac{1}{9} + \frac{1}{27} = \frac{1 \cdot 3}{9 \cdot 3} + \frac{1}{27} = \frac{3}{27} + \frac{1}{27} = \frac{3+1}{27} = \frac{4}{27}\)

Ответ: \(\frac{4}{27}\)