Решение примеров:

a) $$3\frac{7}{8} + 4\frac{5}{12} = 3 + 4 + \frac{7}{8} + \frac{5}{12} = 7 + \frac{7 \cdot 3 + 5 \cdot 2}{24} = 7 + \frac{21 + 10}{24} = 7 + \frac{31}{24} = 7 + 1\frac{7}{24} = 8\frac{7}{24}$$

б) $$4\frac{3}{14} + 3\frac{2}{21} = 4 + 3 + \frac{3}{14} + \frac{2}{21} = 7 + \frac{3 \cdot 3 + 2 \cdot 2}{42} = 7 + \frac{9 + 4}{42} = 7 + \frac{13}{42} = 7\frac{13}{42}$$

в) $$2 - \frac{14}{17} = \frac{2 \cdot 17 - 14}{17} = \frac{34 - 14}{17} = \frac{20}{17} = 1\frac{3}{17}$$

г) $$4\frac{8}{15} - 2\frac{1}{30} = 4 - 2 + \frac{8}{15} - \frac{1}{30} = 2 + \frac{8 \cdot 2 - 1}{30} = 2 + \frac{16 - 1}{30} = 2 + \frac{15}{30} = 2 + \frac{1}{2} = 2\frac{1}{2}$$

д) $$8\frac{1}{10} - 3\frac{1}{6} = 8 - 3 + \frac{1}{10} - \frac{1}{6} = 5 + \frac{3 - 5}{30} = 5 - \frac{2}{30} = 5 - \frac{1}{15} = \frac{5 \cdot 15 - 1}{15} = \frac{75 - 1}{15} = \frac{74}{15} = 4\frac{14}{15}$$

е) $$11 - 7\frac{4}{7} = 11 - 7 - \frac{4}{7} = 4 - \frac{4}{7} = \frac{4 \cdot 7 - 4}{7} = \frac{28 - 4}{7} = \frac{24}{7} = 3\frac{3}{7}$$