\( 5 \frac{7}{19} = \frac{5 \cdot 19 + 7}{19} = \frac{95 + 7}{19} = \frac{102}{19} \)
\( 1 \frac{12}{19} = \frac{1 \cdot 19 + 12}{19} = \frac{19 + 12}{19} = \frac{31}{19} \)
\( c = \frac{102}{19} - \frac{31}{19} = \frac{102 - 31}{19} = \frac{71}{19} \)
\( \frac{71}{19} = 3 \frac{14}{19} \)
Ответ: \( c = 3 \frac{14}{19} \).