\(\frac{4^{12} · 4^{20}}{4^{29}} = \frac{4^{12+20}}{4^{29}} = \frac{4^{32}}{4^{29}} = 4^{32-29} = 4^3 = 64\)
\(\frac{32 · 2^6}{4^4} = \frac{2^5 · 2^6}{(2^2)^4} = \frac{2^{5+6}}{2^8} = \frac{2^{11}}{2^8} = 2^{11-8} = 2^3 = 8\)