Решение:
- \( x^2 - 20^2 = 0 \)
\( x^2 - 400 = 0 \)
\( x^2 = 400 \)
\( x = \pm \sqrt{400} \)
\( x = \pm 20 \) - \( 81 - 16y^2 = 0 \)
\( 16y^2 = 81 \)
\( y^2 = \frac{81}{16} \)
\( y = \pm \sqrt{\frac{81}{16}} \)
\( y = \pm \frac{9}{4} \) - \( (5-y)^2 - y(y+8.1) = 25 \)
\( 25 - 10y + y^2 - y^2 - 8.1y = 25 \)
\( 25 - 10y - 8.1y = 25 \)
\( -10y - 8.1y = 25 - 25 \)
\( -18.1y = 0 \)
\( y = 0 \)
Ответ: a) x = ±20; б) y = ±9/4; в) y = 0.