2. Представьте в виде дроби: а) \(\frac{3-2a}{2a}-\frac{1-a^2}{a^2}\); б) \(\frac{1}{3x+y}-\frac{1}{3x-y}\); в) \(\frac{3}{b-2}-\frac{4-3b}{b^2-2b}\).

1. \[\frac{3-2a}{2a}-\frac{1-a^2}{a^2}=\frac{a(3-2a)-2(1-a^2)}{2a^2}=\frac{3a-2}{2a^2}.\]
2. \[\frac{1}{3x+y}-\frac{1}{3x-y}=\frac{3x-y-(3x+y)}{(3x+y)(3x-y)}=-\frac{2y}{9x^2-y^2}.\]
3. \[\frac{3}{b-2}-\frac{4-3b}{b^2-2b}=\frac{3b-(4-3b)}{b(b-2)}=\frac{6b-4}{b(b-2)}=\frac{2(3b-2)}{b(b-2)}.\]

Ответ: а) \(\frac{3a-2}{2a^2}\); б) \(-\frac{2y}{9x^2-y^2}\); в) \(\frac{2(3b-2)}{b(b-2)}\).