Вопрос:

2. Найдите значение выражения -7,8 – d, если: 1) d = -3,9; 2) d = 5,4; 3) d = 3\(\frac{1}{3}\); 4) d = -2\(\frac{7}{15}\).

Ответ:

Решение:

  1. \(-7,8 - d = -7,8 - (-3,9) = -7,8 + 3,9 = -3,9\)
  2. \(-7,8 - d = -7,8 - 5,4 = -13,2\)
  3. \(-7,8 - d = -7,8 - 3\(\frac{1}{3}\) = -7,8 - 3\(\frac{10}{30}\) = -7\(\frac{24}{30}\) - 3\(\frac{10}{30}\) = -10\(\frac{34}{30}\) = -11\(\frac{4}{30}\) = -11\(\frac{2}{15}\)
    \(-7,8 = -7\(\frac{8}{10}\) = -7\(\frac{4}{5}\) = -7\(\frac{24}{30}\)
    \(3\frac{1}{3} = 3\frac{10}{30}\)
    \(-7\frac{24}{30} - 3\frac{10}{30} = -10\frac{34}{30} = -11\frac{4}{30} = -11\frac{2}{15}\)
  4. \(-7,8 - d = -7,8 - (-2\(\frac{7}{15}\)) = -7,8 + 2\(\frac{7}{15}\) = -7\(\frac{4}{5}\) + 2\(\frac{7}{15}\) = -7\(\frac{12}{15}\) + 2\(\frac{7}{15}\) = -5\(\frac{5}{15}\) = -5\(\frac{1}{3}\)
    \(-7,8 = -7\(\frac{8}{10}\) = -7\(\frac{4}{5}\) = -7\(\frac{12}{15}\)
    \(2\frac{7}{15}\)
    \(-7\frac{12}{15} + 2\frac{7}{15} = -5\frac{5}{15} = -5\frac{1}{3}\)

Ответ: 1) -3,9; 2) -13,2; 3) \(-11\frac{2}{15}\); 4) \(-5\frac{1}{3}\).

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