105. Найдите значение выражения: а) 3 3/7 + 1 8/14 · (8 3/5 − 1 3/5); б) 2 5/9 · 2 1/4 − 6 2/9 · 3/8; в) (6 2/5 · 2 11/12 − 16) · 2 1/4; г) (1/2)⁸ · (3 1/3 − 2 8/9)²; д) (3 2/3 − 2 1/2) · 2 1/7 − 1 1/2; е) 12 · (11/12 − 9/10) · (3 − 1 1/8).

1. \(1\frac{8}{14}=1\frac{4}{7}=\frac{11}{7}\), а \(8\frac{3}{5}-1\frac{3}{5}=7\).

   \(3\frac{3}{7}+\frac{11}{7}\cdot7=\frac{24}{7}+11=\frac{101}{7}=14\frac{3}{7}\).

2. \(2\frac{5}{9}\cdot2\frac{1}{4}-6\frac{2}{9}\cdot\frac{3}{8}=\frac{23}{9}\cdot\frac{9}{4}-\frac{56}{9}\cdot\frac{3}{8}=\frac{23}{4}-\frac{7}{3}=\frac{41}{12}=3\frac{5}{12}\).

3. \(6\frac{2}{5}\cdot2\frac{11}{12}=\frac{32}{5}\cdot\frac{35}{12}=\frac{56}{3}\).

   \((\frac{56}{3}-16)\cdot2\frac{1}{4}=\frac{8}{3}\cdot\frac{9}{4}=6\).

4. \(3\frac{1}{3}-2\frac{8}{9}=\frac{10}{3}-\frac{26}{9}=\frac{4}{9}\).

   \((\frac{1}{2})^8\cdot(\frac{4}{9})^2=\frac{1}{256}\cdot\frac{16}{81}=\frac{1}{1296}\).

5. \(3\frac{2}{3}-2\frac{1}{2}=\frac{11}{3}-\frac{5}{2}=\frac{7}{6}\).

   \(\frac{7}{6}\cdot2\frac{1}{7}-1\frac{1}{2}=\frac{7}{6}\cdot\frac{15}{7}-\frac{3}{2}=\frac{5}{2}-\frac{3}{2}=1\).

6. \(\frac{11}{12}-\frac{9}{10}=\frac{1}{60}\), а \(3-1\frac{1}{8}=\frac{15}{8}\).

   \(12\cdot\frac{1}{60}\cdot\frac{15}{8}=\frac{3}{8}\).

Ответ: а) 14 3/7; б) 3 5/12; в) 6; г) 1/1296; д) 1; е) 3/8.