1. Реши уравнения: a) -16 - 1,4a = -0,9a-16; б) - \( \frac{2}{3} \)x + 2,1 = \( \frac{1}{4} \)x - 1,2; в) 8 (-y-2) = -5y - (6-9y); г) -b-( \( \frac{b}{4} + \frac{3}{8} \) ) = \( \frac{1}{2} \) + ( - \( \frac{3b}{8} \) - 0,5); д) \( \frac{6}{-k+11} = \frac{-3}{2k-1} \); e) \( \frac{-0,09}{0,17} = \frac{5-d}{d-13} \).

Решение:

1. а) \( -16 - 1,4a = -0,9a - 16 \)
   \( -1,4a + 0,9a = -16 + 16 \)
   \( -0,5a = 0 \)
   \( a = 0 \)
2. б) \( - \frac{2}{3}x + 2,1 = \frac{1}{4}x - 1,2 \)
   \( 2,1 + 1,2 = \frac{1}{4}x + \frac{2}{3}x \)
   \( 3,3 = \frac{3+8}{12}x \)
   \( \frac{33}{10} = \frac{11}{12}x \)
   \( x = \frac{33}{10} \cdot \frac{12}{11} = \frac{3 \cdot 12}{10} = \frac{36}{10} = 3,6 \)
3. в) \( 8(-y-2) = -5y - (6-9y) \)
   \( -8y - 16 = -5y - 6 + 9y \)
   \( -8y - 16 = 4y - 6 \)
   \( -16 + 6 = 4y + 8y \)
   \( -10 = 12y \)
   \( y = -\frac{10}{12} = -\frac{5}{6} \)
4. г) \( -b - (\frac{b}{4} + \frac{3}{8}) = \frac{1}{2} + (- \frac{3b}{8} - 0,5) \)
   \( -b - \frac{b}{4} - \frac{3}{8} = \frac{1}{2} - \frac{3b}{8} - \frac{1}{2} \)
   \( -b - \frac{b}{4} - \frac{3}{8} = -\frac{3b}{8} \)
   \( -b - \frac{b}{4} = \frac{3}{8} - \frac{3b}{8} \)
   \( -\frac{5b}{4} = \frac{3-3b}{8} \)
   \( -10b = 3 - 3b \)
   \( -10b + 3b = 3 \)
   \( -7b = 3 \)
   \( b = -\frac{3}{7} \)
5. д) \( \frac{6}{-k+11} = \frac{-3}{2k-1} \)
   \( 6(2k-1) = -3(-k+11) \)
   \( 12k - 6 = 3k - 33 \)
   \( 12k - 3k = -33 + 6 \)
   \( 9k = -27 \)
   \( k = -3 \)
6. е) \( \frac{-0,09}{0,17} = \frac{5-d}{d-13} \)
   \( -0,09(d-13) = 0,17(5-d) \)
   \( -0,09d + 1,17 = 0,85 - 0,17d \)
   \( -0,09d + 0,17d = 0,85 - 1,17 \)
   \( 0,08d = -0,32 \)
   \( d = -\frac{0,32}{0,08} = -4 \)

Ответ: а) a = 0; б) x = 3,6; в) y = -\(\frac{5}{6}\); г) b = -\(\frac{3}{7}\); д) k = -3; е) d = -4.