37) √a² + 12ab + 36b² при a = 7 2/5 и b = 3/5;

37) $$√{a^2 + 12ab + 36b^2}, a = 7\frac{2}{5}, b = \frac{3}{5}$$

$$√{a^2 + 12ab + 36b^2} = √{(a + 6b)^2} = |a + 6b|$$

$$a = 7\frac{2}{5} = \frac{37}{5}, b = \frac{3}{5}$$

$$\left| \frac{37}{5} + 6 \cdot \frac{3}{5} \right| = \left| \frac{37}{5} + \frac{18}{5} \right| = \frac{55}{5} = 11$$

Ответ: 11