1) 0,8√400 + 1/7√49; 2) √0,36 * 16; 3) √36 * 24; 4) √27 * √3 - √28 / √7

Question

Вопрос:

1) 0,8√400 + 1/7√49; 2) √0,36 * 16; 3) √36 * 24; 4) √27 * √3 - √28 / √7

Ответ:

Accepted Answer

1) 0,8√400 + 1/7√49 = 0.8 * 20 + 1/7 * 7 = 16 + 1 = 17 2) √0,36 * 16 = √(36/100 * 16) = √(9/25 * 16) = 3/5 * 4 = 12/5 = 2.4 3) √36 * 24 = √(36 * 4) = √144 = 12 4) √27 * √3 - √28 / √7 = √(27 * 3) - √(28/7) = √81 - √4 = 9 - 2 = 7

1) 0,8√400 + 1/7√49; 2) √0,36 * 16; 3) √36 * 24; 4) √27 * √3 - √28 / √7

Ответ:

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