14) $$\frac{4k}{9} \cdot \frac{27}{20} =$$

$$\frac{4k}{9} \cdot \frac{27}{20} = \frac{4k \cdot 27}{9 \cdot 20} = \frac{108k}{180} = \frac{36k \cdot 3}{36 \cdot 5} = \frac{3k}{5}$$

Ответ: $$\frac{3k}{5}$$