10) \(6 \cdot (\frac{1}{3})^2 - 17 \cdot \frac{1}{3}\)

10) $$6 \cdot (\frac{1}{3})^2 - 17 \cdot \frac{1}{3} = 6 \cdot \frac{1}{9} - \frac{17}{3} = \frac{6}{9} - \frac{17}{3} = \frac{2}{3} - \frac{17}{3} = -\frac{15}{3} = -5$$ Ответ: -5