10). \(-3\frac{1}{7}\cdot(-8)-2,9:0,1+\frac{1}{2}\) 12). \((6-2\frac{4}{5})\cdot3\frac{1}{3}-1\frac{3}{5}\) 14). \(4\frac{1}{6}:(1\frac{1}{2}-\frac{3}{5})+\frac{7}{6}\) 16). \(7\cdot2\frac{6}{53}+\frac{7}{12}:(\frac{7}{9}-\frac{3}{5}))\)

1. \(-3\frac{1}{7}\cdot(-8)-2,9:0,1+\frac{1}{2} = -\frac{22}{7} \cdot (-8) - 2.9 : 0.1 + \frac{1}{2} = \frac{176}{7} - 29 + \frac{1}{2} = \frac{176 \cdot 2 - 29 \cdot 14 + 7}{14} = \frac{352 - 406 + 7}{14} = \frac{359 - 406}{14} = \frac{-47}{14} = -3\frac{5}{14}\)
2. \((6-2\frac{4}{5})\cdot3\frac{1}{3}-1\frac{3}{5} = (6 - \frac{14}{5}) \cdot \frac{10}{3} - \frac{8}{5} = (\frac{30 - 14}{5}) \cdot \frac{10}{3} - \frac{8}{5} = \frac{16}{5} \cdot \frac{10}{3} - \frac{8}{5} = \frac{32}{3} - \frac{8}{5} = \frac{32 \cdot 5 - 8 \cdot 3}{15} = \frac{160 - 24}{15} = \frac{136}{15} = 9\frac{1}{15}\)
3. \(4\frac{1}{6}:(1\frac{1}{2}-\frac{3}{5})+\frac{7}{6} = \frac{25}{6} : (\frac{3}{2} - \frac{3}{5}) + \frac{7}{6} = \frac{25}{6} : (\frac{3 \cdot 5 - 3 \cdot 2}{10}) + \frac{7}{6} = \frac{25}{6} : \frac{9}{10} + \frac{7}{6} = \frac{25}{6} \cdot \frac{10}{9} + \frac{7}{6} = \frac{25 \cdot 5}{3 \cdot 9} + \frac{7}{6} = \frac{125}{27} + \frac{7}{6} = \frac{125 \cdot 2 + 7 \cdot 9}{54} = \frac{250 + 63}{54} = \frac{313}{54} = 5\frac{43}{54}\)
4. \(7\cdot2\frac{6}{53}+\frac{7}{12}:(\frac{7}{9}-\frac{3}{5}) = 7 \cdot \frac{112}{53} + \frac{7}{12} : (\frac{7 \cdot 5 - 3 \cdot 9}{45}) = \frac{784}{53} + \frac{7}{12} : (\frac{35 - 27}{45}) = \frac{784}{53} + \frac{7}{12} : \frac{8}{45} = \frac{784}{53} + \frac{7}{12} \cdot \frac{45}{8} = \frac{784}{53} + \frac{7 \cdot 15}{4 \cdot 8} = \frac{784}{53} + \frac{105}{32} = \frac{784 \cdot 32 + 105 \cdot 53}{53 \cdot 32} = \frac{25088 + 5565}{1696} = \frac{30653}{1696} = 18\frac{17}{1696}\)

Ответ: -47/14; 136/15; 313/54; 30653/1696