Решебник по алгебре 9 класс Макарычев Задание 34

 

$$\boxed{{\displaystyle \text{34 (34).}\text{ }\text{Еуроки - ДЗ без мороки}}}$$

$$Напромежутке[0;4]$$

$$леднагревался;$$

$$(4;10)-ледтаяли$$

$$превращалсявводу;$$

$[10;16]-воданагревалась.$

$$\boxed{{\displaystyle \text{34. }\text{ОК ГДЗ - домашка на 5}}}$$

$$\mathbf{\text{а)}}2,4\cdot {10}^{-2}+0,0125\cdot {10}^3=$$

$$=0,024+12,5=12,524$$

$$2,4\cdot {10}^{-2}-0,0125\cdot {10}^3=$$

$$=0,024-12,5=-12,476$$

$$2,4\cdot {10}^{-2}\cdot 0,0125\cdot {10}^3=$$

$$=2,4\cdot {10}^{-2}\cdot 12,5=30\cdot {10}^{-2}=$$

$$=0,3$$

$$2,4\cdot {10}^{-2}:0,0125\cdot {10}^3=$$

$$=24000:125\cdot {10}^{-5}=$$

$$=192\cdot {10}^{-5}$$

$$\mathbf{\text{б)}}{(1,3\cdot {10}^{-2})}^2=1,69\cdot {10}^{-4};$$

$$1,69\cdot {10}^{-4}+5,2\cdot {10}^{-5}=$$

$$={10}^{-4}\cdot (1,69+5,2\cdot {10}^{-1})=$$

$$={10}^{-4}\cdot (1,69+0,52)=$$

$$=2,21\cdot {10}^{-4}$$

$$1,69\cdot {10}^{-4}-5,2\cdot {10}^{-5}=$$

$$={10}^{-4}\cdot (1,69-5,2\cdot {10}^{-1})=$$

$$={10}^{-4}\cdot (1,69-0,52)=$$

$$=1,17\cdot {10}^{-4}$$

$$1,69\cdot {10}^{-4}\cdot 5,2\cdot {10}^{-5}=$$

$$=8,788\cdot {10}^{-9}$$

$$1,69\cdot {10}^{-4}:5,2\cdot {10}^{-5}=$$

$$=169:520\cdot {10}^1=$$

$$=169:52=3,25$$

$$\mathbf{\text{в)}}15,4\cdot {10}^6+0,044\cdot {10}^7=$$

$$={10}^6\cdot (15,4+0,044\cdot 10)=$$

$$={10}^6\cdot (15,4+0,44)=$$

$$=15,84\cdot {10}^6$$

$$15,4\cdot {10}^6-0,044\cdot {10}^7=$$

$$={10}^6\cdot (15,4-0,044\cdot 10)=$$

$$={10}^6\cdot (15,4-0,44)=$$

$$=14,96\cdot {10}^6$$

$$15,4\cdot {10}^6\cdot 0,044\cdot {10}^7=$$

$$=15,4\cdot 0,044\cdot {10}^{13}=$$

$$=154\cdot 44\cdot {10}^9=6776\cdot {10}^9$$

$$15,4\cdot {10}^6:0,044\cdot {10}^7=$$

$$=15400:44\cdot {10}^{-1}=$$

$$=1540:44=35$$

$$\mathbf{\text{г)}}{(3,5\cdot {10}^{-3})}^2=12,25\cdot {10}^{-6};$$

$${(7\cdot {10}^{-4})}^2=49\cdot {10}^{-8}$$

$$12,25\cdot {10}^{-6}+49\cdot {10}^{-8}=$$

$$={10}^{-6}(12,25+49\cdot {10}^{-2})=$$

$$={10}^{-6}(12,25+0,49)=$$

$$=12,74\cdot {10}^{-6}$$

$$12,25\cdot {10}^{-6}-49\cdot {10}^{-8}=$$

$$={10}^{-6}(12,25-49\cdot {10}^{-2})=$$

$$={10}^{-6}(12,25-0,49)=$$

$$=11,76\cdot {10}^{-6}$$

$$12,25\cdot {10}^{-6}\cdot 49\cdot {10}^{-8}=$$

$$=600,25\cdot {10}^{-14}$$

$$12,25\cdot {10}^{-6}:49\cdot {10}^{-8}=$$

$$=1225:4900\cdot {10}^2=$$

$$=1225:49=25$$