Решебник по алгебре 8 класс Макарычев ФГОС Задание 320

\[\boxed{\text{320\ (320).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[\textbf{а)}\ x^{2} = 36\]

\[x = \pm \sqrt{36}\]

\[x = \pm 6.\]

\[\textbf{б)}\ x^{2} = 0,49\]

\[x = \pm \sqrt{0,49}\]

\[x = \pm 0,7.\]

\[\textbf{в)}\ x^{2} = 121\]

\[x = \pm \sqrt{121}\]

\[x = \pm 11.\]

\[\textbf{г)}\ x^{2} = 11\]

\[x = \pm \sqrt{11}.\]

\[\textbf{д)}\ x^{2} = 8\]

\[x = \pm \sqrt{8}\]

\[x = \pm 2\sqrt{2}.\]

\[\textbf{е)}\ x^{2} = 2,5\]

\[x = \pm \sqrt{2,5}\]

\[x = \pm 5\sqrt{0,1}.\]

\[\boxed{\text{320.}\text{\ }\text{еуроки}\text{-}\text{ответы}\text{\ }\text{на}\text{\ }\text{пятёрку}}\]

Выражение \(\sqrt{a}\) имеет смысл при любом a≥0.

\[\textbf{а)}\ \sqrt{2x}\text{\ \ }при\ \ \ \ \ \ 2x \geq 0;\ \ x \geq 0\]

\[\textbf{б)}\ \sqrt{- x}\ \ при\ \ - x \geq 0;\ \ \ x \leq 0\ \]