5. Запишите в виде неправильной дроби числа: а) 3; 5; 4; 2; б) 2; 4; 5; 27 со знаменателями 7 и 11.

5. Запишите в виде неправильной дроби числа:

a)

• $$3\frac{1}{2} = \frac{3 \cdot 2 + 1}{2} = \frac{7}{2}$$
• $$5\frac{2}{3} = \frac{5 \cdot 3 + 2}{3} = \frac{17}{3}$$
• $$4\frac{3}{7} = \frac{4 \cdot 7 + 3}{7} = \frac{31}{7}$$
• $$2\frac{9}{10} = \frac{2 \cdot 10 + 9}{10} = \frac{29}{10}$$

б)

• $$2 = \frac{2}{1} = \frac{2 \cdot 7}{1 \cdot 7} = \frac{14}{7}$$
• $$2 = \frac{2}{1} = \frac{2 \cdot 11}{1 \cdot 11} = \frac{22}{11}$$
• $$4 = \frac{4}{1} = \frac{4 \cdot 7}{1 \cdot 7} = \frac{28}{7}$$
• $$4 = \frac{4}{1} = \frac{4 \cdot 11}{1 \cdot 11} = \frac{44}{11}$$
• $$5 = \frac{5}{1} = \frac{5 \cdot 7}{1 \cdot 7} = \frac{35}{7}$$
• $$5 = \frac{5}{1} = \frac{5 \cdot 11}{1 \cdot 11} = \frac{55}{11}$$
• $$27 = \frac{27}{1} = \frac{27 \cdot 7}{1 \cdot 7} = \frac{189}{7}$$
• $$27 = \frac{27}{1} = \frac{27 \cdot 11}{1 \cdot 11} = \frac{297}{11}$$

Ответ:

a)

• $$\frac{7}{2}$$
• $$\frac{17}{3}$$
• $$\frac{31}{7}$$
• $$\frac{29}{10}$$

б)

• $$\frac{14}{7}$$ и $$\frac{22}{11}$$
• $$\frac{28}{7}$$ и $$\frac{44}{11}$$
• $$\frac{35}{7}$$ и $$\frac{55}{11}$$
• $$\frac{189}{7}$$ и $$\frac{297}{11}$$