1 Задание (на оценку «3») 1. 2$$\frac{1}{3}$$+1$$\frac{1}{2}$$+3$$\frac{1}{6}$$ 2. 3$$\frac{1}{4}$$-(2$$\frac{1}{2}$$-1$$\frac{3}{8}$$) 3. $$\frac{7}{12}$$\cdot$$2$$\frac{8}{14}$$\div$$\frac{5}{17}$$\cdot$$\frac{10}{34}$$

Ответ: 7; 1$$\frac{23}{24}$$; 1

1. 2$$\frac{1}{3}$$+1$$\frac{1}{2}$$+3$$\frac{1}{6}$$ =$$\frac{7}{3}$$ +$$\frac{3}{2}$$ +$$\frac{19}{6}$$ =$$\frac{14}{6}$$ +$$\frac{9}{6}$$ +$$\frac{19}{6}$$ =$$\frac{14+9+19}{6}$$ =$$\frac{42}{6}$$ = 7
2. 3$$\frac{1}{4}$$-(2$$\frac{1}{2}$$-1$$\frac{3}{8}$$) =$$\frac{13}{4}$$-($$\frac{5}{2}$$-$$\frac{11}{8}$$) =$$\frac{13}{4}$$-($$\frac{20}{8}$$-$$\frac{11}{8}$$) =$$\frac{13}{4}$$-$$\frac{9}{8}$$ =$$\frac{26}{8}$$-$$\frac{9}{8}$$ =$$\frac{17}{8}$$ = 2$$\frac{1}{8}$$
3. $$\frac{7}{12}$$\cdot$$2$$\frac{8}{14}$$\div$$\frac{5}{17}$$\cdot$$\frac{10}{34}$$ =$$\frac{7}{12}$$\cdot$$\frac{36}{14}$$\div$$\frac{5}{17}$$\cdot$$\frac{10}{34}$$ =$$\frac{1}{2}$$\cdot$$3$$\frac{17}{5}$$\cdot$$\frac{10}{34}$$ =$$\frac{1}{2}$$\cdot$$\frac{17}{5}$$\cdot$$\frac{10}{34}$$ = 1

Ответ: 7; 1$$\frac{23}{24}$$; 1