Вопрос:
Задание 8. Выполните действие:
Ответ:
Раздел А
- \( \frac{1}{2} + \frac{x}{3} = \frac{3 + 2x}{6} \)
- \( \frac{2}{5} + \frac{a}{2} = \frac{4 + 5a}{10} \)
- \( \frac{y}{7} - \frac{x}{3} = \frac{3y - 7x}{21} \)
- \( \frac{2}{a} + \frac{1}{3} = \frac{6 + a}{3a} \)
- \( \frac{x}{y} + \frac{2}{3} = \frac{3x + 2y}{3y} \)
- \( \frac{5}{a} + \frac{1}{b} = \frac{5b + a}{ab} \)
- \( \frac{c}{7} - \frac{2}{a} = \frac{ac - 14}{7a} \)
- \( \frac{8}{b} - \frac{a}{c} = \frac{8c - ab}{bc} \)
- \( \frac{ab}{x} \cdot \frac{y}{3} = \frac{aby}{3x} \)
- \( 3x \cdot \frac{2y}{b} = \frac{6xy}{b} \)
Раздел Б
- \( \frac{a}{4} + \frac{b}{8} = \frac{2a + b}{8} \)
- \( \frac{n}{10} - \frac{m}{5} = \frac{n - 2m}{10} \)
- \( \frac{6}{25} + \frac{a}{100} = \frac{24 + a}{100} \)
- \( \frac{1}{2a} - \frac{1}{2b} = \frac{b - a}{2ab} \)
- \( \frac{1}{6x} - \frac{1}{6y} = \frac{y - x}{6xy} \)
- \( \frac{3}{5c} - \frac{2}{15c} = \frac{9 - 2}{15c} = \frac{7}{15c} \)
- \( \frac{x}{3a} + \frac{3x}{6a} = \frac{x}{3a} + \frac{x}{2a} = \frac{2x + 3x}{6a} = \frac{5x}{6a} \)
- \( \frac{a}{28m} - \frac{a}{7m} = \frac{a - 4a}{28m} = \frac{-3a}{28m} \)
- \( \frac{b}{10x} + \frac{a}{15x} = \frac{3b + 2a}{30x} \)
- \( \frac{5x}{12a} - \frac{2y}{9a} = \frac{15x - 8y}{36a} \)
Раздел В
- \( \frac{2}{5a} + \frac{1}{6b} = \frac{12b + 5a}{30ab} \)
- \( \frac{1}{7c} - \frac{1}{5d} = \frac{5d - 7c}{35cd} \)
- \( \frac{5}{8x} + \frac{1}{12y} = \frac{15y + 2x}{24xy} \)
- \( \frac{11}{12k} - \frac{5}{18c} = \frac{33c - 10k}{36kc} \)
- \( \frac{a}{6x} + \frac{4}{9xy} = \frac{3ay + 8}{18xy} \)
- \( \frac{3}{20bc} - \frac{x}{15c} = \frac{9 - 4bx}{60bc} \)
- \( \frac{3}{ab} + \frac{2}{ac} = \frac{3c + 2b}{abc} \)
- \( \frac{1}{xy} - \frac{1}{xz} = \frac{z - y}{xyz} \)
- \( \frac{2}{ab} - \frac{2}{cx} = \frac{2cx - 2ab}{abcx} \)
- \( \frac{5}{abx} + \frac{z}{acy} = \frac{5cy + abz}{abcxy} \)
Раздел Г
- \( \frac{5}{x} + \frac{2}{x^2} = \frac{5x + 2}{x^2} \)
- \( \frac{8}{a^3} - \frac{3}{a} = \frac{8 - 3a^2}{a^3} \)
- \( \frac{5}{x^3} + \frac{a}{x^2} = \frac{5 + ax}{x^3} \)
- \( \frac{1}{b^5} + \frac{c}{b^3} = \frac{1 + cb^2}{b^5} \)
- \( \frac{4}{3a} + \frac{5}{a^2} = \frac{4a + 15}{3a^2} \)
- \( \frac{x}{8c^2} - \frac{5}{12c} = \frac{3x - 10c}{24c^2} \)
- \( \frac{9}{10b^2} - \frac{8}{2b^3} = \frac{9b - 160}{20b^3} \)
- \( \frac{a}{16n^2} + \frac{b}{24n^3} = \frac{3an + 2b}{48n^3} \)
- \( \frac{y}{12c^4} + \frac{x}{18c^6} = \frac{3yc^2 + 2x}{36c^6} \)
- \( \frac{5}{ab^7} - \frac{3}{cb^5} = \frac{5c - 3ab^2}{ab^7c} \)