Задание 2. Найдите корень уравнения. 1) 3x+5+(x+5)=(1-x)+4; 2) x-3-4(x+1)=5(4-x)−1; 5) -3x+1+(x-5)=5(3-x)+5; 6) -x-4+5(x+3)=5(−1−x)-2;

Решение:

1. \(3x+5+(x+5)=(1-x)+4\)

\(4x+10 = 5-x\)

\(4x+x = 5-10\)

\(5x = -5\)

\(x = -1\)

2. \(x-3-4(x+1)=5(4-x)−1\)

\(x-3-4x-4 = 20-5x-1\)

\(-3x-7 = 19-5x\)

\(-3x+5x = 19+7\)

\(2x = 26\)

\(x = 13\)

3. \(-3x+1+(x-5)=5(3-x)+5\)

\(-2x-4 = 15-5x+5\)

\(-2x-4 = 20-5x\)

\(-2x+5x = 20+4\)

\(3x = 24\)

\(x = 8\)

4. \(-x-4+5(x+3)=5(−1−x)-2\)

\(-x-4+5x+15 = -5-5x-2\)

\(4x+11 = -7-5x\)

\(4x+5x = -7-11\)

\(9x = -18\)

\(x = -2\)

Ответ: 1) -1; 2) 13; 5) 8; 6) -2.