Задание 2. Найдите значение выражения 1) (+230)-4 2) (-3)-9 15 3) (2+2)-16 4) (111-37)4 5)(1+2)-30 6)(1-2)-26 7) 1음:(+2) 11 8) 34:15-4 1 10) 1:(1-2) 12 11) 3/(1+2)* 4:20-3*

1) \((\frac{9}{6} + 2\frac{8}{3}) \cdot 4 = (\frac{9}{6} + \frac{8}{3}) \cdot 4 = (\frac{9}{6} + \frac{16}{6}) \cdot 4 = \frac{25}{6} \cdot 4 = \frac{25 \cdot 4}{6} = \frac{100}{6} = \frac{50}{3} \approx 16.67\)

2) \((4\frac{9}{1} - 3\frac{15}{1}) \cdot 9 = (49 - 315) \cdot 9 = -266 \cdot 9 = -2394\)

3) \((2\frac{2}{3} + 2\frac{4}{5}) \cdot 16 = (\frac{8}{3} + \frac{14}{5}) \cdot 16 = (\frac{40}{15} + \frac{42}{15}) \cdot 16 = \frac{82}{15} \cdot 16 = \frac{82 \cdot 16}{15} = \frac{1312}{15} \approx 87.47\)

4) \((\frac{1}{11} - 3\frac{7}{7}) \cdot 4 = (\frac{1}{11} - 3) \cdot 4 = (\frac{1}{11} - \frac{33}{11}) \cdot 4 = -\frac{32}{11} \cdot 4 = -\frac{32 \cdot 4}{11} = -\frac{128}{11} \approx -11.64\)

5) \((1\frac{3}{4} + 2\frac{5}{4}) \cdot 30 = (\frac{7}{4} + \frac{13}{4}) \cdot 30 = \frac{20}{4} \cdot 30 = 5 \cdot 30 = 150\)

6) \((1\frac{13}{3} - 2\frac{4}{3}) \cdot 26 = (\frac{16}{3} - \frac{10}{3}) \cdot 26 = \frac{6}{3} \cdot 26 = 2 \cdot 26 = 52\)

7) \(1\frac{8}{12} : (1\frac{17}{7} + 2\frac{11}{7}) = \frac{20}{12} : (\frac{24}{7} + \frac{25}{7}) = \frac{5}{3} : \frac{49}{7} = \frac{5}{3} : 7 = \frac{5}{3} \cdot \frac{1}{7} = \frac{5}{21} \approx 0.24\)

8) \(3\frac{4}{5} : (1\frac{15}{5} - 4) = \frac{19}{5} : (\frac{20}{5} - 4) = \frac{19}{5} : (4 - 4) = \frac{19}{5} : 0 = \text{не определено}\)

9) \(4\frac{7}{23} : (2\frac{3}{10} + 4\frac{19}{10}) = \frac{99}{23} : (\frac{23}{10} + \frac{59}{10}) = \frac{99}{23} : \frac{82}{10} = \frac{99}{23} : \frac{41}{5} = \frac{99}{23} \cdot \frac{5}{41} = \frac{99 \cdot 5}{23 \cdot 41} = \frac{495}{943} \approx 0.52\)

10) \(1\frac{12}{1} : (1\frac{13}{5} - 2\frac{18}{5}) = 13 : (\frac{8}{5} - \frac{28}{5}) = 13 : (-\frac{20}{5}) = 13 : (-4) = -3.25\)

11) \(3\frac{1}{2} : (1\frac{4}{15} + 2\frac{10}{9}) = \frac{7}{2} : (\frac{19}{15} + \frac{28}{9}) = \frac{7}{2} : (\frac{57}{45} + \frac{140}{45}) = \frac{7}{2} : \frac{197}{45} = \frac{7}{2} \cdot \frac{45}{197} = \frac{7 \cdot 45}{2 \cdot 197} = \frac{315}{394} \approx 0.80\)

12) \(4\frac{1}{4} : (2\frac{7}{10} - 3\frac{8}{1}) = \frac{17}{4} : (\frac{27}{10} - 3) = \frac{17}{4} : (\frac{27}{10} - \frac{30}{10}) = \frac{17}{4} : (-\frac{3}{10}) = \frac{17}{4} \cdot (-\frac{10}{3}) = -\frac{17 \cdot 10}{4 \cdot 3} = -\frac{170}{12} = -\frac{85}{6} \approx -14.17\)