x^2 + 8x + 16 = (3x - 4)^2

The equation is $$x^2 + 8x + 16 = (3x - 4)^2$$.

Expand the right side: $$(3x - 4)^2 = (3x)^2 - 2(3x)(4) + 4^2 = 9x^2 - 24x + 16$$.

The equation becomes $$x^2 + 8x + 16 = 9x^2 - 24x + 16$$.

Subtract $$x^2 + 8x + 16$$ from both sides: $$0 = 8x^2 - 32x$$.

Factor out $$8x$$: $$0 = 8x(x - 4)$$.

The solutions are $$x = 0$$ and $$x = 4$$.