(x-3)² = 3x(x+4) = (x+4)²+3x(2x-4)= (4-5)(x+5) (x-2)(x+2)-x(x+3)=

Ответ: Сейчас решим!

Решение:

1) \[ (x-3)^2 - 3x(x+4) = \] \[ x^2 - 6x + 9 - 3x^2 - 12x = \] \[ -2x^2 - 18x + 9\] 2) \[ (x+4)^2 + 1.5x(2x-4) = \] \[ x^2 + 8x + 16 + 3x^2 - 6x = \] \[ 4x^2 + 2x + 16 \] 3) \[ (x-2)(x+2) - x(x+3) = \] \[ x^2 - 4 - x^2 - 3x = \] \[ -3x - 4\] 4) \[ 5x(x-3) + (x-5)(x+5) = \] \[ 5x^2 - 15x + x^2 - 25 = \] \[ 6x^2 - 15x - 25\]

Ответ:

\[(x-3)^2 - 3x(x+4) = -2x^2 - 18x + 9\] \[(x+4)^2 + 1.5x(2x-4) = 4x^2 + 2x + 16\] \[(x-2)(x+2) - x(x+3) = -3x - 4\] \[ 5x(x-3) + (x-5)(x+5) = 6x^2 - 15x - 25\]

Ответ: -2x^2 - 18x + 9, 4x^2 + 2x + 16, -3x - 4, 6x^2 - 15x - 25