\[\frac{4}{9} + \frac{2}{9} \cdot \frac{9}{13} = \frac{4}{9} + \frac{2 \cdot 9}{9 \cdot 13} = \frac{4}{9} + \frac{18}{117} = \frac{4}{9} + \frac{2}{13} = \frac{4 \cdot 13 + 2 \cdot 9}{9 \cdot 13} = \frac{52 + 18}{117} = \frac{70}{117}\]
\[\frac{11}{9} - \frac{4}{11} \cdot \frac{11}{5} = \frac{11}{9} - \frac{4 \cdot 11}{11 \cdot 5} = \frac{11}{9} - \frac{44}{55} = \frac{11}{9} - \frac{4}{5} = \frac{11 \cdot 5 - 4 \cdot 9}{9 \cdot 5} = \frac{55 - 36}{45} = \frac{19}{45}\]
\[2 \cdot \frac{1}{8} + \frac{12}{7} \cdot \frac{7}{3} = \frac{2}{8} + \frac{12 \cdot 7}{7 \cdot 3} = \frac{1}{4} + \frac{12}{3} = \frac{1}{4} + 4 = \frac{1 + 4 \cdot 4}{4} = \frac{1 + 16}{4} = \frac{17}{4} = 4\frac{1}{4}\]
\[\left(\frac{2}{3}\right)^2 + \frac{13}{21} \cdot \frac{7}{26} - \frac{5}{18} = \frac{4}{9} + \frac{13 \cdot 7}{21 \cdot 26} - \frac{5}{18} = \frac{4}{9} + \frac{91}{546} - \frac{5}{18} = \frac{4}{9} + \frac{1}{6} - \frac{5}{18} = \frac{4 \cdot 2 + 1 \cdot 3 - 5}{18} = \frac{8 + 3 - 5}{18} = \frac{6}{18} = \frac{1}{3}\]
\[\left(\frac{3}{7}\right)^2 - \frac{1}{2} \cdot \frac{49}{16} + \left(\frac{1}{3}\right)^3 = \frac{9}{49} - \frac{1 \cdot 49}{2 \cdot 16} + \frac{1}{27} = \frac{9}{49} - \frac{49}{32} + \frac{1}{27}\]
Приводить к общему знаменателю достаточно долго, поэтому оставим так.
Ответ: а) \(\frac{70}{117}\); б) \(\frac{19}{45}\); г) \(4\frac{1}{4}\); д) \(\frac{1}{3}\); e) \(\frac{9}{49} - \frac{49}{32} + \frac{1}{27}\)