Вычитание обыкновенных дробей Вариант 2.2.1

Решение:

1. \( \frac{1}{2} - \frac{1}{3} = \frac{3}{6} - \frac{2}{6} = \frac{1}{6} \)
2. \( \frac{3}{4} - \frac{3}{8} = \frac{6}{8} - \frac{3}{8} = \frac{3}{8} \)
3. \( \frac{1}{4} - \frac{1}{6} = \frac{3}{12} - \frac{2}{12} = \frac{1}{12} \)
4. \( 4 - \frac{5}{11} = \frac{44}{11} - \frac{5}{11} = \frac{39}{11} \)
5. \( 12\frac{11}{40} - 8 = 4\frac{11}{40} = \frac{4 \cdot 40 + 11}{40} = \frac{160+11}{40} = \frac{171}{40} \)
6. \( 6\frac{11}{31} - \frac{13}{31} = 5\frac{31+11}{31} - \frac{13}{31} = 5\frac{42}{31} - \frac{13}{31} = 5\frac{42-13}{31} = 5\frac{29}{31} \)
7. \( \frac{4}{5} - \frac{7}{15} = \frac{12}{15} - \frac{7}{15} = \frac{5}{15} = \frac{1}{3} \)
8. \( 7\frac{1}{4} - 4\frac{1}{2} = 7\frac{1}{4} - 4\frac{2}{4} = 6\frac{4+1}{4} - 4\frac{2}{4} = 6\frac{5}{4} - 4\frac{2}{4} = 2\frac{3}{4} = \frac{2 \cdot 4 + 3}{4} = \frac{8+3}{4} = \frac{11}{4} \)