Вопрос:

Вычислите: а) \(1\frac{2}{7}:\frac{3}{56}\); б) \(1\frac{3}{4}:\frac{7}{10}+\frac{1}{4}\); в) \(\left(27\frac{9}{10}-17\frac{4}{5}\right):\frac{3}{5}\); г) \(\left(12{,}22:4{,}7+0{,}15\cdot2\right):0{,}5\).

Ответ:

  1. \(1\frac{2}{7}:\frac{3}{56}=\frac{9}{7}\cdot\frac{56}{3}=24\).
  2. \(1\frac{3}{4}:\frac{7}{10}+\frac14=\frac74\cdot\frac{10}{7}+\frac14=\frac52+\frac14=2\frac34\).
  3. \(\left(27\frac9{10}-17\frac45\right):\frac35=\left(27\frac9{10}-17\frac8{10}\right):\frac35=10\frac1{10}:\frac35=\frac{101}{10}\cdot\frac53=\frac{101}{6}=16\frac56\).
  4. \(\left(12{,}22:4{,}7+0{,}15\cdot2\right):0{,}5=\left(2{,}6+0{,}3\right):0{,}5=2{,}9:0{,}5=5{,}8\).