\(\frac{5}{14} + \frac{4}{7} = \frac{5}{14} + \frac{4 \cdot 2}{7 \cdot 2} = \frac{5}{14} + \frac{8}{14} = \frac{5+8}{14} = \frac{13}{14}\)
\(6\frac{1}{2} = \frac{6 \cdot 2 + 1}{2} = \frac{12+1}{2} = \frac{13}{2}\)
\(\frac{13}{14} : \frac{13}{2} = \frac{13}{14} \cdot \frac{2}{13} = \frac{13 \cdot 2}{14 \cdot 13} = \frac{2}{14} = \frac{1}{7}\)
\(-1 + \frac{1}{7} = -\frac{7}{7} + \frac{1}{7} = \frac{-7+1}{7} = -\frac{6}{7}\)
Ответ: -⁶/₇